Thread: similar logarithm problem!

e^2x-7e^x+10

bit confused on how to find the x?

Lets make

Now we have



which can be factored as follows



by the null factor law



and bring our original unknown back into the picture





Does this make sense?

Originally Posted by frozenflames

e^2x-7e^x+10

bit confused on how to find the x?

This can't be solved because it doesn't equal anything. Also, use parentheses to avoid confusion. You could mean e^(2)*x or e^(2x).

Thanks Jameson, my solution only assumes the expression is equal to zero.

okay, that makes a lot of sense so there are two answers technically and I forgot to take the ln of the 2 and 5. that is where i was going wrong..thanks so much!

Originally Posted by pickslides

Thanks Jameson, my solution only assumes the expression is equal to zero.

Given the way the problem worked out, it seems that was a good assumption. It's just not good to see people solve for things that can't be solved.