e^2x-7e^x+10

bit confused on how to find the x?

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- October 2nd 2009, 02:07 PMfrozenflamessimilar logarithm problem!
e^2x-7e^x+10

bit confused on how to find the x? - October 2nd 2009, 02:53 PMJameson
- October 2nd 2009, 02:53 PMpickslides

Lets make

Now we have

which can be factored as follows

by the null factor law

and bring our original unknown back into the picture

Does this make sense? - October 2nd 2009, 02:57 PMpickslides
Thanks Jameson, my solution only assumes the expression is equal to zero.

- October 2nd 2009, 02:59 PMfrozenflames
okay, that makes a lot of sense so there are two answers technically and I forgot to take the ln of the 2 and 5. that is where i was going wrong..thanks so much!

- October 2nd 2009, 03:13 PMJameson