I can't seem to figure out for what value of the constant c is the function f continuous on negative infinity to positive infinity
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Originally Posted by frozenflames I can't seem to figure out for what value of the constant c is the function f continuous on negative infinity to positive infinity For it to be continous it needs to be continous at b=9 This mean that $\displaystyle \lim_{b \to 9^-}f(b)=f(9)=\lim_{b \to 9^+}f(b)$ so we need to sove $\displaystyle 9c+5=81c-5 \iff 10=72c \iff c=\frac{5}{32}$
Last edited by TheEmptySet; Oct 3rd 2009 at 07:50 AM. Reason: I had a dyslexic moment. Error corrected.
Originally Posted by TheEmptySet For it to be continous it needs to be continous at b=9 This mean that $\displaystyle \lim_{b \to 9^-}f(b)=f(9)=\lim_{b \to 9^+}f(b)$ so we need to sove $\displaystyle 9c+5=81c-5 \iff 10=72c \iff c=\frac{32}{5}$ I think you did the final part of the math wrong. It should be 10/72 not the other way around right?
Originally Posted by frozenflames I think you did the final part of the math wrong. It should be 10/72 not the other way around right? You shouldn't need re-assurance on how to solve $\displaystyle 10 = 72c$. The typo is obvious.
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