The function is defined for real values of x. By writing it in completed-square form, find its range.
f(x)=x^2-6x-+10
Thank you!!
Hi there
To complete the square you should consider the following
$\displaystyle f(x)=x^2-6x-10$
You need to find a new constant term by taking the middle term, halving it then squaring it. This gives...
$\displaystyle f(x)=(x^2-6x+9)-10-9$
$\displaystyle f(x)=(x^2-6x+9)-19$
$\displaystyle f(x)=(x-3)^2-19$
Now the square is complete.
The notation in your original post is ambigous. Defunkt's example may be what you're looking for.