# Help completing the square.

• Oct 2nd 2009, 07:47 AM
Oasis1993
Help completing the square.
The function is defined for real values of x. By writing it in completed-square form, find its range.

f(x)=x^2-6x-+10

Thank you!!
• Oct 2nd 2009, 07:52 AM
Defunkt
$x^2-6x+10 = x^2-6x+9+1 = (x-3)^2 +1$

can you follow?
• Oct 2nd 2009, 08:00 AM
pickslides
Hi there

To complete the square you should consider the following

$f(x)=x^2-6x-10$

You need to find a new constant term by taking the middle term, halving it then squaring it. This gives...

$f(x)=(x^2-6x+9)-10-9$

$f(x)=(x^2-6x+9)-19$

$f(x)=(x-3)^2-19$

Now the square is complete.

The notation in your original post is ambigous. Defunkt's example may be what you're looking for.