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- Oct 2nd 2009, 06:29 AM #1

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- Sep 2009
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## Set y = 0?

The question first tells me to graph the function to determine any x-intercepts.

y = 20(2/X+1 - 3/x)

When I put it in my calculator, I got x-intercept = (1,0)

Now it tells me to set y = 0 to confirm this result.

So,

0 = 20(2/X+1 - 3/x)

I started working in the brackets:

(2x)/(x)(x + 1) - (3x+1)/(x)(x+1)

(-x+1) / (x)(x+1)

Is this right?

If so, what do I do next? What do I do with the 20?

- Oct 2nd 2009, 08:08 AM #2

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- Oct 2nd 2009, 09:03 AM #3

- Oct 2nd 2009, 10:47 AM #4