What is the maximum volume possible from a piece of cardboard that is made into a cube, that measures 16 inches by 12 inches?

[___________ ]

[ __________ ]

[___________ ] 12 - 2x

[____________]

16in - 2x

- A Box with no top.

$\displaystyle L = 12-2x$

$\displaystyle W = 16 - 2x$

$\displaystyle n = x $

$\displaystyle V = 172 - 32x - 24x + 4x^2(x)$

$\displaystyle V = 172x - 32x^2 - 24x^2 + 4x^2$

$\displaystyle 4x^3 - 24x^2 - 32x^2 + 172x$

$\displaystyle 4x^3 - 56x^2 +172x $

$\displaystyle 4x(x^2 - 14x + 43) $

$\displaystyle How to solve for X.$

this is where I got stuck.

Thank you