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Math Help - Logarithm Equation

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    Logarithm Equation

    How do you solve this? I'm confused.

     (\log x)^2 = \log x^2
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  2. #2
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    Quote Originally Posted by JSB1917 View Post
    How do you solve this? I'm confused.

     (\log x)^2 = \log x^2
    (log(x))^2 - 2log(x) = 0

    This is now a quadratic in log(x) which can be solved like any other quadratic but remember the domain restriction on log terms:

    hint: let u = log(x)


    Spoiler:
    log(x)(log(x)-2) = 0

    log(x) = 0 (which can be discounted since we can't take the log of 0)

    log(x) = 2

    <br />
x = 10^2 = 100
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