Originally Posted by
pickslides $\displaystyle x^2y - xy +1 = x$
$\displaystyle x^2y - xy = x-1$
$\displaystyle y(x^2 - x) = x-1$
$\displaystyle y = \frac{x-1}{(x^2 - x)}$
$\displaystyle y = \frac{x-1}{x(x - 1)}$
$\displaystyle y = \frac{1}{x}$ Mr F adds: $\displaystyle {\color{red}x \neq 1}$. The graph of this hyperbola has a hole at (1, 1).
what do you know about this function?