# Thread: [SOLVED] Using a graphing calculator to solve the equation

1. ## [SOLVED] Using a graphing calculator to solve the equation

I have a TI-89 Titanium. We have been using the calc to solve the equations by setting everything = 0 and putting in the Y= screen. We then graph, set the value to 0, and find where the line intersects the x-axis for the solution.

On the 89 you can also do solve() and it brings you to the same answer.

However, in the problem ln (2x) - -x+3 I do not see an intersection of the x axis when graphing this, but when using solve() i get x=0.2429601

Any ideas if the answer is actually no solution or do I go with the 0.2429601 ?

2. "the problem ln (2x) - -x+3", i don't understand this . . . please clarify

3. Originally Posted by spoken428
in the problem ln (2x) - -x+3 I do not see an intersection of the x axis when graphing this, but when using solve() i get x=0.2429601
When simplified, your expression is actually $ln(2x)+x+3$. When you plug 0.2429601 into that expression the result is 2.5212492, which is not zero.