Given

$\displaystyle f(x)=\frac{x^2-1}{|x-1|}$

$\displaystyle \lim_{x\to1+}{f(x)}$

$\displaystyle \lim_{x\to1-}{f(x)}$

Is the numerator reducible? I am just not seeing the method I should start with, a push in the correct direction would be appreciated.