The problem is and the difference quotient to evaluate is the answer in the book is -1/ax. How did they arrive at that conclusion? Thanks. Evan
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Originally Posted by Evan.Kimia The problem is and the difference quotient to evaluate is the answer in the book is -1/ax. How did they arrive at that conclusion? start with... getting a common denominator in the numerator... factor a negative out of the denominator... cancel the (a-x) and rewrite...
i plugged in f(x) and f(a) into the equation and got... im not sure how to simplify this numerator correctly.
Originally Posted by pflo start with... getting a common denominator in the numerator... factor a negative out of the denominator... cancel the (a-x) and rewrite... I see that you factored out a-x by -1 in order to cancel out the a-x above, but what method would i use to get a common denominator in the numerator? Thanks.
Originally Posted by Evan.Kimia I see that you factored out a-x by -1 in order to cancel out the a-x above, but what method would i use to get a common denominator in the numerator? The numerator is . Think about how you would do this: . To get a common denominator you would multiply the by and the by , right? Same thing here using x and a instead of 2 and 3.
Thank you so much everyone.
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