I'm having a lot of trouble with finding the domain of this question: $\displaystyle sqrt(8x-4)/sqrt(x)$ I get [.5, inf), which I'm told is wrong.
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From the denominator it is clear that $\displaystyle x\neq 0 $ or $\displaystyle x \neq \mathbb{R}^-$ In the numerator $\displaystyle 8x-4 > 0$ giving $\displaystyle x > \frac{1}{2}$ Your solution sounds good to me.
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