Question is in the link. I just can't figure these 2 out.
Thanks a lot....again!
http://img9.imageshack.us/img9/7561/60225025.jpg (that exponent on the second equation is a -t)
Auger
Question is in the link. I just can't figure these 2 out.
Thanks a lot....again!
http://img9.imageshack.us/img9/7561/60225025.jpg (that exponent on the second equation is a -t)
Auger
$\displaystyle (\frac{1}{32})^{4x} = 1024$
All these numbers are powers of two so it can be expressed as:
$\displaystyle \frac{1}{2^{20x}} = 2^{-20x} = 2^{10}$
If the bases are equal then the exponents must be equal: $\displaystyle -20x = 10$. Should be clear that $\displaystyle x = -0.5$
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$\displaystyle \frac{20}{3+4e^{-t}} = 5$
Take the reciprocal of both sides and then multiply by 20
$\displaystyle 3+4e^{-t} = 4$
Take 3 and then divide by 4:
$\displaystyle e^{-t} = \frac{1}{4}$
$\displaystyle -t = -ln(4) = -2ln(2)$
$\displaystyle t = 2\,ln2$