Results 1 to 4 of 4

Math Help - Solve for X

  1. #1
    Member
    Joined
    Sep 2009
    Posts
    181

    Solve for X

    Hello!

    Can someone please help me with this problem?

    8x^2e^x + x^3e^x = 0

    I'm still having problems understanding the steps...

    Thanks!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member woof's Avatar
    Joined
    Apr 2009
    Posts
    31
    The key to these problems is that e^x is a common term to each, so it can be factored out, along with other powers of x.

    8x^2e^x + x^3e^x =x^2e^x (8+ x)= 0

    When you factor out the e^x, remember, it can never be zero.

    Then the only way for x^2e^x (8+ x)= 0 to be true is for

    e^x=0, which can't happen, so you can just ignore this factor at this point, and

    you have either x^2= 0 or  (8+ x)= 0
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Sep 2009
    Posts
    181
    great thanks! so to my undestanding e^x can always be eliminated as long as it has a common factor?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member pacman's Avatar
    Joined
    Jul 2009
    Posts
    448
    flipboi:"great thanks! so to my undestanding e^x can always be eliminated as long as it has a common factor?"

    if there is a common factor in every TERM, then do the factoring as may..
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. need to solve summation equation to solve sum(x2)
    Posted in the Statistics Forum
    Replies: 2
    Last Post: July 16th 2010, 10:29 PM
  2. how do i solve this IVP: y'=y^2 -4
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: February 24th 2010, 11:14 AM
  3. Replies: 1
    Last Post: June 9th 2009, 10:37 PM
  4. how do i solve this?
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 2nd 2008, 02:58 PM
  5. how to solve ..
    Posted in the Advanced Algebra Forum
    Replies: 0
    Last Post: August 2nd 2008, 08:17 AM

Search Tags


/mathhelpforum @mathhelpforum