Evaluate the function at the indicated value of $\displaystyle x$. I have to figure out what power times 8 equals 2. Anybody??
Follow Math Help Forum on Facebook and Google+
Originally Posted by BeSweeet Evaluate the function at the indicated value of $\displaystyle x$. I have to figure out what power times 8 equals 2. Anybody?? Do you know anything about fractional exponents? Because your answer is close. Its REAL close.
Originally Posted by VonNemo19 Do you know anything about fractional exponents? Because your answer is close. Its REAL close. Seriously? Because I don't know how to figure this one out :\.
Originally Posted by BeSweeet Seriously? Because I don't know how to figure this one out :\. $\displaystyle x^{1/2}=\sqrt{x}$ $\displaystyle x^{1/3}=\sqrt[3]{x}$ $\displaystyle x^{1/4}=\sqrt[4]{x}$ $\displaystyle (27)^{1/3}=3$ Get the picture? So.................. $\displaystyle (8)^{?}=2$ ?
Not really .
Originally Posted by BeSweeet Evaluate the function at the indicated value of $\displaystyle x$. I have to figure out what power times 8 equals 2. Anybody?? $\displaystyle \log_8 2 = x \Rightarrow 8^x = 2 \Rightarrow (2^3)^x = 2 \Rightarrow 2^{3x} = 2 \Rightarrow 2^{3x} = 2^1$ .... Solve for x.
Ah, ok. We went through this in class and he got 3 :\. log2^8 8=s^y 2^3=2^y y=3
Originally Posted by BeSweeet Ah, ok. We went through this in class and he got 3 :\. log2^8 8=s^y 2^3=2^y y=3 That's not the question that was asked. Can you get the answer to the question that was asked by solving for x in my previous post?
View Tag Cloud