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Math Help - Evaluating log

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    Evaluating log

    Evaluate the function at the indicated value of x.


    I have to figure out what power times 8 equals 2. Anybody??
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by BeSweeet View Post
    Evaluate the function at the indicated value of x.


    I have to figure out what power times 8 equals 2. Anybody??
    Do you know anything about fractional exponents? Because your answer is close.

    Its REAL close.
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    Quote Originally Posted by VonNemo19 View Post
    Do you know anything about fractional exponents? Because your answer is close.

    Its REAL close.
    Seriously? Because I don't know how to figure this one out :\.
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  4. #4
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by BeSweeet View Post
    Seriously? Because I don't know how to figure this one out :\.
    x^{1/2}=\sqrt{x}

    x^{1/3}=\sqrt[3]{x}

    x^{1/4}=\sqrt[4]{x}


    (27)^{1/3}=3

    Get the picture?

    So.................. (8)^{?}=2 ?
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    Not really .
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    Quote Originally Posted by BeSweeet View Post
    Evaluate the function at the indicated value of x.


    I have to figure out what power times 8 equals 2. Anybody??
    \log_8 2 = x \Rightarrow 8^x = 2 \Rightarrow (2^3)^x = 2 \Rightarrow 2^{3x} = 2 \Rightarrow 2^{3x} = 2^1 .... Solve for x.
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  7. #7
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    Ah, ok. We went through this in class and he got 3 :\.

    log2^8
    8=s^y
    2^3=2^y
    y=3
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    Quote Originally Posted by BeSweeet View Post
    Ah, ok. We went through this in class and he got 3 :\.

    log2^8
    8=s^y
    2^3=2^y
    y=3
    That's not the question that was asked. Can you get the answer to the question that was asked by solving for x in my previous post?
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