1. ## Evaluating log

Evaluate the function at the indicated value of $\displaystyle x$.

I have to figure out what power times 8 equals 2. Anybody??

2. Originally Posted by BeSweeet
Evaluate the function at the indicated value of $\displaystyle x$.

I have to figure out what power times 8 equals 2. Anybody??

Its REAL close.

3. Originally Posted by VonNemo19

Its REAL close.
Seriously? Because I don't know how to figure this one out :\.

4. Originally Posted by BeSweeet
Seriously? Because I don't know how to figure this one out :\.
$\displaystyle x^{1/2}=\sqrt{x}$

$\displaystyle x^{1/3}=\sqrt[3]{x}$

$\displaystyle x^{1/4}=\sqrt[4]{x}$

$\displaystyle (27)^{1/3}=3$

Get the picture?

So.................. $\displaystyle (8)^{?}=2$ ?

5. Not really .

6. Originally Posted by BeSweeet
Evaluate the function at the indicated value of $\displaystyle x$.

I have to figure out what power times 8 equals 2. Anybody??
$\displaystyle \log_8 2 = x \Rightarrow 8^x = 2 \Rightarrow (2^3)^x = 2 \Rightarrow 2^{3x} = 2 \Rightarrow 2^{3x} = 2^1$ .... Solve for x.

7. Ah, ok. We went through this in class and he got 3 :\.

log2^8
8=s^y
2^3=2^y
y=3

8. Originally Posted by BeSweeet
Ah, ok. We went through this in class and he got 3 :\.

log2^8
8=s^y
2^3=2^y
y=3
That's not the question that was asked. Can you get the answer to the question that was asked by solving for x in my previous post?