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Math Help - Find the Limits

  1. #1
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    Find the Limits

    I'm pretty sure i do something wrong here, i get both limits to 0. Any help would be greatly appreciated!
    \lim\frac{4n+1}{\sqrt{4n^2-3}} and \lim\sqrt{n^2-3n}-n

    n->infinity (for both, couldnt figure out how to add it to the lim with the latex)
    Last edited by takamura; September 28th 2009 at 07:01 AM. Reason: wrote in the wrong numbers xD
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  2. #2
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    Quote Originally Posted by takamura View Post
    I'm pretty sure i do something wrong here, i get both limits to 0. Any help would be greatly appreciated!
    \lim\frac{3n+2}{\sqrt{4n^2-1}} and \sqrt{n^2-5n}-n

    n->infinity (for both, couldnt figure out how to add it to the lim with the latex)
    What value of x are you making the function tend to?
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  3. #3
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    Quote Originally Posted by takamura View Post
    \lim_{n\rightarrow\infty}\frac{4n+1}{\sqrt{4n^2-3}}
    Try dividing, top and bottom, by n. (Inside the square root, of course, this will turn into n^2.)

    Quote Originally Posted by takamura View Post
    \lim_{n\rightarrow\infty}\sqrt{n^2-3n}-n
    Try putting this over "1", and multiplying, top and bottom, by the conjugate of the original expression. Then divide, top and bottom, by n.

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