# Find the Limits

• Sep 28th 2009, 05:21 AM
takamura
Find the Limits
I'm pretty sure i do something wrong here, i get both limits to 0. Any help would be greatly appreciated! ;)
$\lim\frac{4n+1}{\sqrt{4n^2-3}}$ and $\lim\sqrt{n^2-3n}-n$

n->infinity (for both, couldnt figure out how to add it to the lim with the latex)
• Sep 28th 2009, 05:23 AM
Prove It
Quote:

Originally Posted by takamura
I'm pretty sure i do something wrong here, i get both limits to 0. Any help would be greatly appreciated! ;)
$\lim\frac{3n+2}{\sqrt{4n^2-1}}$ and $\sqrt{n^2-5n}-n$

n->infinity (for both, couldnt figure out how to add it to the lim with the latex)

What value of x are you making the function tend to?
• Sep 28th 2009, 06:40 AM
stapel
Quote:

Originally Posted by takamura
$\lim_{n\rightarrow\infty}\frac{4n+1}{\sqrt{4n^2-3}}$

Try dividing, top and bottom, by n. (Inside the square root, of course, this will turn into n^2.)

Quote:

Originally Posted by takamura
$\lim_{n\rightarrow\infty}\sqrt{n^2-3n}-n$

Try putting this over "1", and multiplying, top and bottom, by the conjugate of the original expression. Then divide, top and bottom, by n.

(Wink)