I am having difficulty finding the solution to: Find the parametrization for the left of the parabola y = x^2 - 4x + 3 Help anyone.
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Originally Posted by jmastrella I am having difficulty finding the solution to: Find the parametrization for the left of the parabola y = x^2 - 4x + 3 Help anyone. $\displaystyle y = (x - 2)^2 - 1$ so one possible answer is $\displaystyle x = t + 2$ and $\displaystyle y = t^2 - 1$ for $\displaystyle t <0$.
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