# Math Help - Inverse of a function help!

1. ## Inverse of a function help!

So I am asked to find the inverse of the functon: f(x) = (4x-1)/(2x+3)

so y=f(x) and interchange x with y...

So I start by multiplying both sides by 2y+3 to get x(2y+3) = 4y-1

Now I am not really sure what to do. I tried making it 2y+3-4y = -1/x

then -2y = -1/x -3

and -y = (-1/x -3)/2

But I think this is still the wrong answer. Can anyone lead me onto the right track? Thanks!

2. Originally Posted by Landyach
So I am asked to find the inverse of the functon: f(x) = (4x-1)/(2x+3)
$x = \frac{4y-1}{2y+3}$

$2xy+3x = 4y-1$

$2xy - 4y = -3x -1$

$y(2x - 4) = -(3x+1)$

$y = -\frac{3x+1}{2x-4}$

3. Originally Posted by skeeter
$x = \frac{4y-1}{2y+3}$

$2xy+3x = 4y-1$

$2xy - 4y = -3x -1$

$y(2x - 4) = -(3x+1)$

$y = -\frac{3x+1}{2x-4}$
thanks so much!