Find a formula for the inverse of the function.
y = ln(x + 1)
I know that the inverse of ln(x) = e^x, but i cant figure out how to solve the inverse of ln(x+1). I tried checking my work by plugging in 3 for x and seeing if my inverse function puts out the result of ln(3+1) but no luck. Any ideas?
yes that did work. I just forgot alot of algebra. The method for getting e^x-1 would just be subtracting 1 by both sides then just putting in the inverse of ln(x) (which is e^x)?
also, how would i go about finding (f - 1)(1) and f(f -1)(1) of this? i know arctan is the inverse of tan..
That's correct.
I don't quite understand the question. If you want to find the inverse ofalso, how would i go about finding (f - 1)(1) and f(f -1)(1) of this? i know arctan is the inverse of tan..
then you must write it as:
and then change the subject of the formula (i.e. solve for x), so that it reads x=...
The inverse cannot be found in terms of elementary functions. Read here: http://www.mathhelpforum.com/math-he...-function.html