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Math Help - Help with the Goldman Equation =)

  1. #1
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    Help with the Goldman Equation =)

    Hi guys,

    I'm having trouble with this equation. Could someone please help me out by explaining to me, how to solve for b. I know the answer is 0.02 but don't know how to get it. BTW, this is the goldman equation.


    -71=58log[(5/125) + (b120/b12)]

    THANK YOU
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  2. #2
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    I worked on this a bit. Could someone confirm if my method is correct?

    -71=58log[(5/125) + (b120/b12)]

    I simplified the equation to:

    -1.22 = log [(5/125) + (b120/b12)]

    10^-1.22 = (5/125) (b120/b12)
    0.06 - 0.04 = b120/b12
    0.02 = ratio of b120/b12

    I don't if you can simplified for value of b.

    Any suggestions?
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  3. #3
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by MATHDUDE2 View Post
    I worked on this a bit. Could someone confirm if my method is correct?

    -71=58log[(5/125) + (b120/b12)]

    I simplified the equation to:

    -1.22 = log [(5/125) + (b120/b12)]

    10^-1.22 = (5/125) (b120/b12)
    0.06 - 0.04 = b120/b12
    0.02 = ratio of b120/b12

    I don't if you can simplified for value of b.

    Any suggestions?
    The b120 and b12 terms...are they b_{120} and b_{12}?

    If so, then you can't simplify it any further.
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  4. #4
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    I know it can be simplified, however I'm not sure how to go about doing it. The answer to this question is b=0.02.

    I'm having trouble figuring out how to solve for b with the log rules.
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