Thread: Help with the Goldman Equation =)

Hi guys,

I'm having trouble with this equation. Could someone please help me out by explaining to me, how to solve for b. I know the answer is 0.02 but don't know how to get it. BTW, this is the goldman equation.


-71=58log[(5/125) + (b120/b12)]

THANK YOU

I worked on this a bit. Could someone confirm if my method is correct?

-71=58log[(5/125) + (b120/b12)]

I simplified the equation to:

-1.22 = log [(5/125) + (b120/b12)]

10^-1.22 = (5/125) (b120/b12)
0.06 - 0.04 = b120/b12
0.02 = ratio of b120/b12

I don't if you can simplified for value of b.

Any suggestions?

Originally Posted by MATHDUDE2

I worked on this a bit. Could someone confirm if my method is correct?

-71=58log[(5/125) + (b120/b12)]

I simplified the equation to:

-1.22 = log [(5/125) + (b120/b12)]

10^-1.22 = (5/125) (b120/b12)
0.06 - 0.04 = b120/b12
0.02 = ratio of b120/b12

I don't if you can simplified for value of b.

Any suggestions?

The b120 and b12 terms...are they and ?

If so, then you can't simplify it any further.

I know it can be simplified, however I'm not sure how to go about doing it. The answer to this question is b=0.02.

I'm having trouble figuring out how to solve for b with the log rules.