Results 1 to 2 of 2

Math Help - Challenge Problem

  1. #1
    Newbie
    Joined
    Sep 2009
    Posts
    11

    Question Challenge Problem

    Given: ax^2+bx+c=0 and (x-p)(x-q)=0,

    Prove: p+q=-b/a and pq=c/a
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Banned
    Joined
    May 2009
    Posts
    471
    Apply the quadratic formula to ax^2+bx+c=0

    The two answers you get are the roots right?

    So let's say you get p,q to be the roots (which is what the question is saying) then you can write the original formula as (x-p)(x-q)=0


    When you get the two roots from the quadratic formula, add them together and you'll get -\frac{b}{a} and multiply them together to get \frac{c}{a}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Challenge Problem
    Posted in the Math Challenge Problems Forum
    Replies: 2
    Last Post: July 12th 2010, 02:07 PM
  2. Challenge problem.
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 21st 2010, 05:55 AM
  3. TA’s Challenge Problem #7
    Posted in the Math Challenge Problems Forum
    Replies: 5
    Last Post: August 7th 2009, 08:39 AM
  4. TA’s Challenge Problem #5
    Posted in the Math Challenge Problems Forum
    Replies: 1
    Last Post: July 14th 2009, 06:44 PM
  5. TA’s Challenge Problem #2
    Posted in the Math Challenge Problems Forum
    Replies: 7
    Last Post: June 9th 2009, 02:35 AM

Search Tags


/mathhelpforum @mathhelpforum