1. ## Challenge Problem

Given: $ax^2+bx+c=0$ and $(x-p)(x-q)=0$,

Prove: $p+q=-b/a$ and $pq=c/a$

2. Apply the quadratic formula to $ax^2+bx+c=0$

The two answers you get are the roots right?

So let's say you get p,q to be the roots (which is what the question is saying) then you can write the original formula as (x-p)(x-q)=0

When you get the two roots from the quadratic formula, add them together and you'll get $-\frac{b}{a}$ and multiply them together to get $\frac{c}{a}$