1. ## Solving Equations

How do I solve this equation:
$\frac{x+4}{8}=1-\frac{x+3}{3}$

I know to get rid of the denominators I multiply
$3(x+4)=8(1-x+3)$

is that right so far or do I only multiply 'x+3' by 8 not 1?

2. Originally Posted by bearhug
How do I solve this equation:
$\frac{x+4}{8}=1-\frac{x+3}{3}$

I know to get rid of the denominators I multiply
$3(x+4)=8(1-x+3)$

is that right so far or do I only multiply 'x+3' by 8 not 1?
Remember 1 can be expressed as a fraction with any non-zero denominator. In this case I would use:

$1 = \frac{3}{3}$

$\frac{x+4}{8} = \frac{3}{3} - \frac{x+3}{3} = \frac{3+x+3}{3} = \frac{x+6}{3}$

3. correction ...

$\frac{3}{3} - \frac{x+3}{3} = \frac{3 -(x+3)}{3} = -\frac{x}{3}$