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Math Help - Solving Equations

  1. #1
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    Solving Equations

    How do I solve this equation:
    \frac{x+4}{8}=1-\frac{x+3}{3}

    I know to get rid of the denominators I multiply
    3(x+4)=8(1-x+3)

    is that right so far or do I only multiply 'x+3' by 8 not 1?
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by bearhug View Post
    How do I solve this equation:
    \frac{x+4}{8}=1-\frac{x+3}{3}

    I know to get rid of the denominators I multiply
    3(x+4)=8(1-x+3)

    is that right so far or do I only multiply 'x+3' by 8 not 1?
    Remember 1 can be expressed as a fraction with any non-zero denominator. In this case I would use:

    1 = \frac{3}{3}

    \frac{x+4}{8} = \frac{3}{3} - \frac{x+3}{3} = \frac{3+x+3}{3} = \frac{x+6}{3}
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  3. #3
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    correction ...

    \frac{3}{3} - \frac{x+3}{3} = \frac{3 -(x+3)}{3} = -\frac{x}{3}
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