# Right Triangle

• January 22nd 2007, 02:45 PM
symmetry
Right Triangle
A right triangle has one vertex on the graph of y = 9 - x^2, where x > 0, at point (x, y), another at the origin and the third on the positive x-axis at point (x, 0). Express the area A of the triangle as a function of x.
• January 22nd 2007, 03:15 PM
ThePerfectHacker
Quote:

Originally Posted by symmetry
A right triangle has one vertex on the graph of y = 9 - x^2, where x > 0, at point (x, y), another at the origin and the third on the positive x-axis at point (x, 0). Express the area A of the triangle as a function of x.

It is the height of the triangle which is $y$ which is $9-x^2$ times the base of the triangle with is $x$ times 1/2.
Thus,
$\frac{1}{2}x(9-x^2)$
• January 22nd 2007, 04:31 PM
symmetry
ok
I thank you for pointing out how easy this question really is.