The Question: $\displaystyle 5x^{7/6}-5=0$ I can get to this part: $\displaystyle x^{7/6}=11$ but I don't know what to do next Thanks for the help!
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what you have is equal to ... $\displaystyle \sqrt[6]{x^{7}} = 11$ hope that this is little easier
Thanks but how can I get the x to be alone
If $\displaystyle x^t = s$, then $\displaystyle x = x^{t \cdot \frac{1}{t}} = s^{ \frac{1}{t}}$ Do you follow?
Sorry still dont follow... Edit: Oh I got it...thank you
Last edited by mr fantastic; Sep 26th 2009 at 03:36 PM. Reason: Merged posts
ok you can see $\displaystyle \sqrt[6]{x^{7}} = 11$ from that... $\displaystyle \sqrt[6]{x^{7}} $ is greater than 0 so $\displaystyle x^{7}= 11^{6} $ or $\displaystyle x = \sqrt[7]{ 11^6 }$
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