# Solving Equation

• September 26th 2009, 09:25 AM
Solving Equation
The Question: $5x^{7/6}-5=0$

I can get to this part: $x^{7/6}=11$ but I don't know what to do next

Thanks for the help!
• September 26th 2009, 09:43 AM
josipive
what you have is equal to ... $\sqrt[6]{x^{7}} = 11$

hope that this is little easier
• September 26th 2009, 09:47 AM
Thanks but how can I get the x to be alone
• September 26th 2009, 11:30 AM
Defunkt
If $x^t = s$, then $x = x^{t \cdot \frac{1}{t}} = s^{ \frac{1}{t}}$

Do you follow?
• September 26th 2009, 12:52 PM
Sorry still dont follow...

Edit: Oh I got it...thank you
• September 28th 2009, 03:20 AM
josipive
ok you can see
$\sqrt[6]{x^{7}} = 11$
from that...
$\sqrt[6]{x^{7}}$
is greater than 0
so

$x^{7}= 11^{6}$
or

$x = \sqrt[7]{ 11^6 }$