The Question: $\displaystyle 5x^{7/6}-5=0$

I can get to this part: $\displaystyle x^{7/6}=11$ but I don't know what to do next

Thanks for the help!

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- Sep 26th 2009, 09:25 AMlil_cookieSolving Equation
The Question: $\displaystyle 5x^{7/6}-5=0$

I can get to this part: $\displaystyle x^{7/6}=11$ but I don't know what to do next

Thanks for the help! - Sep 26th 2009, 09:43 AMjosipive
what you have is equal to ... $\displaystyle \sqrt[6]{x^{7}} = 11$

hope that this is little easier - Sep 26th 2009, 09:47 AMlil_cookie
Thanks but how can I get the

*x*to be alone - Sep 26th 2009, 11:30 AMDefunkt
If $\displaystyle x^t = s$, then $\displaystyle x = x^{t \cdot \frac{1}{t}} = s^{ \frac{1}{t}}$

Do you follow? - Sep 26th 2009, 12:52 PMlil_cookie
Sorry still dont follow...

**Edit:**Oh I got it...thank you - Sep 28th 2009, 03:20 AMjosipive
ok you can see

$\displaystyle \sqrt[6]{x^{7}} = 11$

from that...

$\displaystyle \sqrt[6]{x^{7}} $ is greater than 0

so

$\displaystyle x^{7}= 11^{6} $

or

$\displaystyle x = \sqrt[7]{ 11^6 }$