Hello,
I'm a new user and I was hoping someone can help me with this problem?
Edit: sorry I attached the wrong problem, it's actually:
x^2e^x+xe^2-e^x=0
hope this is clear
Thanks!
Hello,
I'm a new user and I was hoping someone can help me with this problem?
Edit: sorry I attached the wrong problem, it's actually:
x^2e^x+xe^2-e^x=0
hope this is clear
Thanks!
Grandad already answered this
To elaborate you can factor out $\displaystyle e^x$ as it's a common factor:
$\displaystyle x^2e^x+xe^x-e^x= e^x(x^2+x-1) = 0$
Dividing through by $\displaystyle e^x$ (this is allowed because for real x: $\displaystyle e^x > 0$) gives $\displaystyle x^2+x-1 = 0$
Use the quadratic formula to solve for x