# Math Help - can you colve for x?

1. ## can you colve for x?

Solve the equation for x.

Solve the equation for x.

First note that 256=4^4 so we change the question into

$4^{x-x^2}=\frac{1}{(4^4)^x}=\frac{1}{4^{4x}}$

Multiply both sides by $4^{4x}$ to get $4^{4x}\cdot 4^{x-x^2}=1$

$4^{4x+x-x^2}=1$

$4^{5x-x^2}=1$

And we need the exponent to be 0 since $x^0=1$ (you can take the log of both sides, but log 1=0 so we reach the same conclusion)

So now just solve $5x-x^2=0$