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Math Help - can you colve for x?

  1. #1
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    can you colve for x?

    Solve the equation for x.
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  2. #2
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    Quote Originally Posted by Dadillar View Post
    Solve the equation for x.

    First note that 256=4^4 so we change the question into

    4^{x-x^2}=\frac{1}{(4^4)^x}=\frac{1}{4^{4x}}

    Multiply both sides by 4^{4x} to get 4^{4x}\cdot 4^{x-x^2}=1

    4^{4x+x-x^2}=1

    4^{5x-x^2}=1

    And we need the exponent to be 0 since x^0=1 (you can take the log of both sides, but log 1=0 so we reach the same conclusion)

    So now just solve 5x-x^2=0
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