# Math Help - Polynomial Divisions ...help???

1. ## Polynomial Divisions ...help???

Divide the following: (3x^3=4x-1)/(x^2+1) adn write the result in the form f(x)=d(x)*q(x)=r(x)

Thank you so very much

2. Surely a couple of those equal signs should be +, no?

So let me assume the question is $\frac{3x^3+4x-1}{x^2+1}$

$x^2$ goes into $3x^3\quad$ $\quad 3x$ times (as $\frac{3x^3}{x^2}=3x$) so now $3x^3+4x-1-(3x(x^2+1))=$

$=3x^3+4x-1-(3x^3+3x)$

$
=x-1
$

Since the degree of x-1 is 1, which is less than the degree of $x^2+1$ which is 2, we are done, and we have a remainder of x-1

So we get $3x(x^2+1)+(x-1)$

3. oh, sorry, forgot to push shift.yea, 2 of them are equal signs

Thank you so much! Thank you thank you thank you! You just saved my life! Thank you!