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Math Help - Polynomial Divisions ...help???

  1. #1
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    Polynomial Divisions ...help???


    Divide the following: (3x^3=4x-1)/(x^2+1) adn write the result in the form f(x)=d(x)*q(x)=r(x)

    Thank you so very much
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  2. #2
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    Surely a couple of those equal signs should be +, no?


    So let me assume the question is \frac{3x^3+4x-1}{x^2+1}

    x^2 goes into 3x^3\quad \quad 3x times (as \frac{3x^3}{x^2}=3x) so now 3x^3+4x-1-(3x(x^2+1))=

    =3x^3+4x-1-(3x^3+3x)

     <br />
=x-1<br />

    Since the degree of x-1 is 1, which is less than the degree of x^2+1 which is 2, we are done, and we have a remainder of x-1

    So we get 3x(x^2+1)+(x-1)
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  3. #3
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    oh, sorry, forgot to push shift.yea, 2 of them are equal signs

    Thank you so much! Thank you thank you thank you! You just saved my life! Thank you!
    Last edited by mr fantastic; September 23rd 2009 at 11:10 PM. Reason: Merged posts
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