ln(y)=(2/3)*ln(x)
thanks
Actually, no. If you multiply through by a constant, you will end up with the same logarithmic equation, but now multiplied through by a constant.
Instead, you need to raise both sides of the equation as powers on the base e.
There's a good reason for not having know that: it's not true!
However, e^ln(x^(2/3)) does equal x^(2/3).