So I got this problem I had to find the midpoint,slope and distance
for (-3,8) And (5,-2)
I got the midpoint as (1,3)
distance is sqr 165
Which is what the teacher got but as for the slope
I got he got sonething else
I got -5 for a slope
he got y=-5/4x + 17/4
and I have no idea how he got that
I just did the formula y2-y1/x2-x1
equation of a line
also I don't really know how to don't know how he did this
Y=2/5x +b
-4=2/5 (1) + b
ans. -22/5=b
I have no idea how he got the final ans.
Can u please explain it as easy as possible
Thanks
(-3,8) , (5,-2)
I got -5 for a slope
he got y=-5/4x + 17/4
and I have no idea how he got that
I just did the formula y2-y1/x2-x1
Gradient = y2-y1/x2-x1
( 8 - ( - 2 ) ) = 8 + 2 = 10
---------------
. ( -3 - 5 ) . = -8
10/-8 = -5/4 ... slope
y = -(5/4)x + b
insert the values of one of the sets of coordinates for x and y,
say ( -3,8 ) to get
8 = ((-5 *( -3 ))/4 + ( b ( the Y-intercept, the value of y when x = 0 ))
Minus * minus = +
8 = (15/4) + b //Subtract 15/4 from both sides,
b = 8 - ( 15/4 )
b = (4 * 8)/4 - 15/4 //convert 8 into quarters to give...
b = (32 - 15)/4 = 17/4
So the Equation of the line is...
y = -(5/4)x +17/4
====================================
The co-ordinates given are ( 1, -4 )
-4 = ( 2/5 )*1 + b
-4 = ( 2/5 ) + b... as before, subtract the slope from both sides
b = -4 - 2/5
b = -(4 * 5)/5 - 2/5 .......convert 4 into fifths to get...
b = -20/5 - 2/5 = ( - 20 - 2 )/5
b = -22/ 5
So the equation of the line is ...
y = (2/5)x - 22/5
Hi Candy101,
English doesn't seem to be your first language, so I will try to explain what jizer0 did for you in one part of his explanation.
(1)
(2)
(3)
Now, this is where the conversion comes in.
In order to add or subtract fractions, you must have a common denominator. In this case that denominator is 5.
To convert -4 to fifths, we can perform the following exercise:
Therefore,
Now, continue with step (4)
(4)
(5)