Hi, its me again. Hope I'm not asking too many math questions. I know f( f^-1(x)) = x but is it the same for f^-1(f(x)) ?/ If it is; sin^ -1(sin(7(pi/2))) = 7pi/2 ? Thanks !
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if you are in doubt, check it with a calculator, "sin^ -1(sin(7(pi/2))) = 7pi/2"
Originally Posted by pacman if you are in doubt, check it with a calculator, "sin^ -1(sin(7(pi/2))) = 7pi/2" The range of the inverse sin function is, by definition, [-pi/2, pi/2]. Since sin(7 pi/2) = -1 it follows that $\displaystyle \sin^{-1} \left(\sin \left( \frac{7 \pi}{2} \right) \right) = \sin^{-1} (-1) = - \frac{\pi}{2}$.
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