Find the solutions: e^2x-1e^x-6=0 X1= 6 x2= _____???
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please use parenthesis so I can be sure of the order of operations there, as you have it i interpret that as $\displaystyle e^2x-e^x-6$ but if that was correct you wouldn't have included the 1 I dont think
use $\displaystyle e^x= u$ then it is just quad equation
Originally Posted by 11rdc11 use $\displaystyle e^x= u$ then it is just quad equation @OP: $\displaystyle \Rightarrow e^{2x} = u^2$. Originally Posted by B-lap no brackets ??!! Surely the equation you intend is $\displaystyle e^{2x} - 1 e^x - 6=0$, in which case there ARE brackets: e^(2x).
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