# Thread: solutions of expondential equation.

1. ## solutions of expondential equation.

Find the solutions:

e^2x-1e^x-6=0

X1= 6
x2= _____???

2. please use parenthesis so I can be sure of the order of operations there, as you have it i interpret that as

$e^2x-e^x-6$ but if that was correct you wouldn't have included the 1 I dont think

3. use $e^x= u$ then it is just quad equation

4. Originally Posted by 11rdc11
use $e^x= u$ then it is just quad equation
@OP: $\Rightarrow e^{2x} = u^2$.

Originally Posted by B-lap
no brackets
??!!

Surely the equation you intend is $e^{2x} - 1 e^x - 6=0$, in which case there ARE brackets: e^(2x).