# solutions of expondential equation.

• September 21st 2009, 06:35 PM
B-lap
solutions of expondential equation.
Find the solutions:

e^2x-1e^x-6=0

X1= 6
x2= _____???
• September 21st 2009, 06:38 PM
artvandalay11
please use parenthesis so I can be sure of the order of operations there, as you have it i interpret that as

$e^2x-e^x-6$ but if that was correct you wouldn't have included the 1 I dont think
• September 21st 2009, 07:11 PM
11rdc11
use $e^x= u$ then it is just quad equation
• September 21st 2009, 08:20 PM
mr fantastic
Quote:

Originally Posted by 11rdc11
use $e^x= u$ then it is just quad equation

@OP: $\Rightarrow e^{2x} = u^2$.

Quote:

Originally Posted by B-lap
no brackets

??!!

Surely the equation you intend is $e^{2x} - 1 e^x - 6=0$, in which case there ARE brackets: e^(2x).