Thread: Finding the zeros

I have this polynomial:

-x^3-3x^2-3x-28

I found it to have one real zero of 4 and two complex zeros. COuld someone check my work please?

Also im not sure how to graph it would i just plot points? Thanks!

Originally Posted by nascar77

I have this polynomial:

-x^3-3x^2-3x-28

I found it to have one real zero of 4 and two complex zeros. COuld someone check my work please?

Also im not sure how to graph it would i just plot points? Thanks!

x = -4 is the zero ... agree with the two complex zeros.

plot points and remember the general shape of a cubic with a negative leading coefficient.