I have this polynomial: -x^3-3x^2-3x-28 I found it to have one real zero of 4 and two complex zeros. COuld someone check my work please? Also im not sure how to graph it would i just plot points? Thanks!
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Originally Posted by nascar77 I have this polynomial: -x^3-3x^2-3x-28 I found it to have one real zero of 4 and two complex zeros. COuld someone check my work please? Also im not sure how to graph it would i just plot points? Thanks! x = -4 is the zero ... agree with the two complex zeros. plot points and remember the general shape of a cubic with a negative leading coefficient.
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