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Math Help - Finding the zeros

  1. #1
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    Finding the zeros

    I have this polynomial:

    -x^3-3x^2-3x-28

    I found it to have one real zero of 4 and two complex zeros. COuld someone check my work please?

    Also im not sure how to graph it would i just plot points? Thanks!
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  2. #2
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    Quote Originally Posted by nascar77 View Post
    I have this polynomial:

    -x^3-3x^2-3x-28

    I found it to have one real zero of 4 and two complex zeros. COuld someone check my work please?

    Also im not sure how to graph it would i just plot points? Thanks!
    x = -4 is the zero ... agree with the two complex zeros.

    plot points and remember the general shape of a cubic with a negative leading coefficient.
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