As x gets large, (this is the same question as the

If you are uncomfortable with that limit, think of it this way: As x gets huge, the denominator of the fraction gets huge and 1 divided by a huge number is basically zero. So the function approaches 2+0=2

When x is positive and large in magnitude, we have the situation i described above, x goes to infinity, so the denominator of the fraction becomes huge and positive. Now they ask is f(x) greater or not, and the answer is since the fraction is positive, even though it's essentially zero, f(x) is greater than this functional value (think of 2+.00000000000001>2)

You should be able to do part c). As gets gets huge in the negative direction, the fraction will still aproach zero but the fraction will now be __________ so f(x) is ___________ than this functional value