Find the solution of the exponential equation. 8^1-x = 8 in terms of logs, or correct to 4 dec. places x= _____________
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Originally Posted by B-lap Find the solution of the exponential equation. 8^1-x = 8 in terms of logs, or correct to 4 dec. places x= _____________ $\displaystyle 8^{1-x} = 8$ May as well use base 8 to make life easy: $\displaystyle 1-x = 1$ $\displaystyle x=0$
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