Determine the equation of the line that passes through the point (2,1) and is:
a. Parallel to the line 3x-2y=4
b. Perpendicular to the line 3x-2y=4
First, I rearranged 3x-2y=4 to be in slope-intercept form:
y=3/2x-2
For part b, I took the slope and put it into point-slope form:
y-1=3/2(x-2)
and got the same thing as slope-intercept form.
I think I'm doing something wrong....
Ok, I think I got it!
For parallel lines, just find the slope, and stick that into point-slope form.
For perpendicular lines, find the slope, and find what other number it will multiply by to equal -1, then stick that into point-slope form.
I just have one [stupid] question: How about did you getting -2/3?
That's really confusing. Where did C go? Did you subtract it from both sides? ( ).
Isn't it easier (for parallel) to just find the slope, and stick it into point-slope form to get my equation, and for perpendicular, find the slope that is equal to -1 (when multiplied by the other number), stick it into point-slope form, and get my equation?