Find the solution of the logarithmic equation

log x + log (x-2) = log (2x)

In terms of logarithms, or correct to four decimal places.

x= _____________

Solve for x:

log (x^5) = (log x)^2

Note there are two solutions, A and B, where A < B

A= ________

B =________

Rewrite the expression:

4 log x - 2 log (x^2 +1) + 5 log (x-1)

as a single logarithm log A. then function

A = _________