Find the solution of the logarithmic equation
log x + log (x-2) = log (2x)
In terms of logarithms, or correct to four decimal places.
x= _____________
Solve for x:
log (x^5) = (log x)^2
Note there are two solutions, A and B, where A < B
A= ________
B =________
Rewrite the expression:
4 log x - 2 log (x^2 +1) + 5 log (x-1)
as a single logarithm log A. then function
A = _________