I have to solve the following inequality, answer written in interval notation
x/(x+3)<_ (-8)/(7(x-6))
BTW <_ is supposed to mean less than or equal to, I was unsure how to insert that.
I get this answer every time, which apparently is wrong:
7x^2-42x<_-8x -24
7x^2-34x+24<_0
(7x-6)(x-4)<_0
[6/7,4]