I have to solve the following inequality, answer written in interval notation

x/(x+3)<_ (-8)/(7(x-6))

BTW <_ is supposed to mean less than or equal to, I was unsure how to insert that.

I get this answer every time, which apparently is wrong:

7x^2-42x<_-8x -24

7x^2-34x+24<_0

(7x-6)(x-4)<_0

[6/7,4]