Thread: How to solve this inequality?

abs((2x-1)/(x-1)) = 3.

I'm trying to figure out what to do and how to finish it since the absolute value is around both (2x+1) and (x-1).

Originally Posted by AlphaRock

abs((2x-1)/(x-1)) = 3.

I'm trying to figure out what to do and how to finish it since the absolute value is around both (2x+1) and (x-1).

Hi AlphaRock,



Let's consider case 1.









Check this solution in your original absolute value equation.

Now consider case 2.









Check this solution in your original absolute value equation.

Originally Posted by AlphaRock

abs((2x-1)/(x-1)) = 3.

I'm trying to figure out what to do and how to finish it since the absolute value is around both (2x+1) and (x-1).

Here is a second way.
Solve:

You should, however, note that what you give is NOT an inequality, it is an equation.