abs((2x-1)/(x-1)) = 3.

I'm trying to figure out what to do and how to finish it since the absolute value is around both (2x+1) and (x-1).

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- Sep 16th 2009, 10:33 PMAlphaRockHow to solve this inequality?
abs((2x-1)/(x-1)) = 3.

I'm trying to figure out what to do and how to finish it since the absolute value is around both (2x+1) and (x-1). - Sep 17th 2009, 04:28 AMmasters
- Sep 17th 2009, 06:31 AMPlato
- Sep 17th 2009, 07:50 AMHallsofIvy
You should, however, note that what you give is NOT an inequality, it is an equation.