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Math Help - Trying to find the zeros of a quadratic?

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    Trying to find the zeros of a quadratic?

    I have this quadratic:

    -2x^2-19x-24

    I need to find its zeros and factor it but I havent had any luck. I also tried the quadratic formula but it produces negative roots? any help is welcomed
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  2. #2
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    Quote Originally Posted by nascar77 View Post
    I have this quadratic:

    -2x^2-19x-24

    I need to find its zeros and factor it but I havent had any luck. I also tried the quadratic formula but it produces negative roots? any help is welcomed
    -2x^2 - 19x - 24 = 0.


    Do you know about the discriminant?

    \Delta = b^2 - 4ac.

    If the discriminant is positive, we have two solutions, if it is 0 we have one solution, and if it is negative we don't have any solutions.

    \Delta = (-19)^2 - 4(-2)(-24)

     = 361 - 192

     = 169.


    Since this is positive, there are two solutions.


    The solutions are given by

    x = \frac{-b \pm \sqrt{\Delta}}{2a}

     = \frac{19 \pm \sqrt{169}}{2(-2)}

     = \frac{19 \pm 13}{-4}

     = \frac{6}{-4} or  = \frac{32}{-4}

     = -\frac{3}{2} or  = -8.
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    thank you
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