The hypotenuse of a right triangle is 11 m. Express the area, A, of the triangle as a function of the length x of one of the legs. I got as far setting it up in the Pythagorean theorem. Any help is really appreciated!!!!
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Originally Posted by Wlu2 The hypotenuse of a right triangle is 11 m. Express the area, A, of the triangle as a function of the length x of one of the legs. I got as far setting it up in the Pythagorean theorem. Any help is really appreciated!!!! one leg is $\displaystyle x$ hypotenuse is $\displaystyle 11$ other leg is $\displaystyle \sqrt{11^2 - x^2}$ triangle area, $\displaystyle A = ?$
Originally Posted by skeeter one leg is $\displaystyle x$ hypotenuse is $\displaystyle 11$ other leg is $\displaystyle \sqrt{11^2 - x^2}$ triangle area, $\displaystyle A = ?$ so A = 1/2(x)($\displaystyle \sqrt{11^2 - x^2}$) ?
Yes.
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