# Math Help - Functions

1. ## Functions

The hypotenuse of a right triangle is 11 m.
Express the area, A, of the triangle as a function
of the length x of one of the legs.

I got as far setting it up in the Pythagorean theorem.

Any help is really appreciated!!!!

2. Originally Posted by Wlu2
The hypotenuse of a right triangle is 11 m.
Express the area, A, of the triangle as a function
of the length x of one of the legs.

I got as far setting it up in the Pythagorean theorem.

Any help is really appreciated!!!!
one leg is $x$

hypotenuse is $11$

other leg is $\sqrt{11^2 - x^2}$

triangle area, $A = ?$

3. Originally Posted by skeeter
one leg is $x$

hypotenuse is $11$

other leg is $\sqrt{11^2 - x^2}$

triangle area, $A = ?$
so A = 1/2(x)( $\sqrt{11^2 - x^2}$) ?

4. Yes.