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Math Help - Functions

  1. #1
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    Functions

    The hypotenuse of a right triangle is 11 m.
    Express the area, A, of the triangle as a function
    of the length x of one of the legs.

    I got as far setting it up in the Pythagorean theorem.

    Any help is really appreciated!!!!
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  2. #2
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    Quote Originally Posted by Wlu2 View Post
    The hypotenuse of a right triangle is 11 m.
    Express the area, A, of the triangle as a function
    of the length x of one of the legs.

    I got as far setting it up in the Pythagorean theorem.

    Any help is really appreciated!!!!
    one leg is x

    hypotenuse is 11

    other leg is \sqrt{11^2 - x^2}

    triangle area, A = ?
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  3. #3
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    Quote Originally Posted by skeeter View Post
    one leg is x

    hypotenuse is 11

    other leg is \sqrt{11^2 - x^2}

    triangle area, A = ?
    so A = 1/2(x)( \sqrt{11^2 - x^2}) ?
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  4. #4
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    Yes.
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