# Thread: help plz

1. ## help plz

4^x+2 = 32^x

you would have to change the base of 4, right? so would it become 32^8x+16? and then cancel the bases and set 8x + 16 = x?

then what's the next step?

hm.

2. Originally Posted by borkthis
4^x+2 = 32^x

you would have to change the base of 4, right? so would it become 32^8x+16? and then cancel the bases and set 8x + 16 = x?

then what's the next step?

hm.
Do you mean

$4^x + 2 = 32^x$

$4^{x+2} = 32^x$

Remember that 4, 2 and 32 are all powers of 2

3. the second form is what i meant. 4 to the power of x + 2. i'm having trouble figuring out the correct way of changing base and solving for x.

4. Originally Posted by borkthis
the second form is what i meant. 4 to the power of x + 2. i'm having trouble figuring out the correct way of changing base and solving for x.
$4^{x+2} = 32^x$

As these are both powers of 2 change to base 2:

$(2^2)^{x+2} = (2^5)^x$

because $(a^b)^c = a^{bc}$

$2^{2x+4} = 2^{5x}$

Now they have the same base so equate the exponents and solve

5. YES! thank you so much! i was doing something completely off.