If $\displaystyle \log_{10} (x - 2) - 3 \log_{10} (2x) = 1 - \log_{10} (y)$, then y is equal to

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- Sep 13th 2009, 03:52 AMuser_5Logarithm Help
If $\displaystyle \log_{10} (x - 2) - 3 \log_{10} (2x) = 1 - \log_{10} (y)$, then y is equal to

- Sep 13th 2009, 04:01 AMmr fantastic
- Sep 13th 2009, 04:08 AMuser_5
Oh, thanks I forgot that 1 can be rewritten like that.

It makes sense now.

Is the answer is $\displaystyle y= \frac {80x^3}{x-2} $ ? - Sep 13th 2009, 04:56 AMFinley
Yes, well done :)

But don't forget the restrictions on X, for the equation to produce a positive number (necessary for a log).

$\displaystyle x>2$ and $\displaystyle x<0$