Solve equation (t+1)^2 - 2(t-1)^2 = 6t-5 x^2-a(3x-2a+b)-b =0 I got no solution for both, is it right?
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Originally Posted by yitsongg Solve equation (t+1)^2 - 2(t-1)^2 = 6t-5 x^2-a(3x-2a+b)-b =0 I got no solution for both, is it right? No. (use the difference of two squares to solve) ----------------- Assuming (Use the quadratic formula to solve in terms of a and b)
Got it first one is t= plus or minus 2 second one is a=3 b=4 x=6
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