1. ## What are the answers to these problems?

Solve equation

(t+1)^2 - 2(t-1)^2 = 6t-5

x^2-a(3x-2a+b)-b =0

I got no solution for both, is it right?

2. Originally Posted by yitsongg
Solve equation

(t+1)^2 - 2(t-1)^2 = 6t-5

x^2-a(3x-2a+b)-b =0

I got no solution for both, is it right?
No.

$
t^2+2t+1 - 2(t^2-2t+1) - 6t + 5 = 0$

$-t^2 + 4 = 0$

(use the difference of two squares to solve)

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$x^2 - 3xa + 2a^2 - ab - b = 0$

Assuming $a \, , \, b \neq \, f(x)$

$x^2 - 3xa + (2a^2-ab-b) = 0$

(Use the quadratic formula to solve in terms of a and b)

3. Got it
first one is t= plus or minus 2

second one is

a=3
b=4
x=6