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Math Help - What are the answers to these problems?

  1. #1
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    What are the answers to these problems?

    Solve equation

    (t+1)^2 - 2(t-1)^2 = 6t-5

    x^2-a(3x-2a+b)-b =0

    I got no solution for both, is it right?
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  2. #2
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    Quote Originally Posted by yitsongg View Post
    Solve equation

    (t+1)^2 - 2(t-1)^2 = 6t-5

    x^2-a(3x-2a+b)-b =0

    I got no solution for both, is it right?
    No.

    <br />
t^2+2t+1 - 2(t^2-2t+1) - 6t + 5 = 0

    -t^2 + 4 = 0

    (use the difference of two squares to solve)


    -----------------

    x^2 - 3xa + 2a^2 - ab - b = 0

    Assuming a \, , \, b \neq \, f(x)

    x^2 - 3xa + (2a^2-ab-b) = 0

    (Use the quadratic formula to solve in terms of a and b)
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  3. #3
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    Got it
    first one is t= plus or minus 2

    second one is

    a=3
    b=4
    x=6
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