does anybody know how to reflect a point over y=mx+b

Thanks

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- January 16th 2007, 06:18 PManime_maniacoordinate geometry
does anybody know how to reflect a point over y=mx+b

Thanks - January 16th 2007, 07:04 PMtopsquark
I'd have to give you a drawing to do this justice and I can't (I need a new scanner. I've been saying that for months now!)

Anyway, my whining aside, I'll give you a couple of ideas to work with.

It's easier to reflect over y = mx. So translate the point "b" units along the y- axis (down if b is positive, up if b is negative), reflect the point over y = mx, then translate the reflected point b units the other way along the y - axis.

Simple example:

Reflect the point (2, 3) over the line y = x - 1.

Translate (2, 3) 1 unit up along the y - axis: (2, 4).

Now reflect (2, 4) over y = x: (4, 2)

Finally, translate (4, 2) 1 unit down along the y - axis: (4, 1)

So reflecting the point (2, 3) over the line y = x - 1 gives the point (4, 1), as you can verify by graphing them directly.

-Dan - January 16th 2007, 08:17 PMThePerfectHacker