Can someone please help me with these problems? I have tried working them out, but I can't seem to get a solution. Please see attachment. Thanks:confused: :(
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Can someone please help me with these problems? I have tried working them out, but I can't seem to get a solution. Please see attachment. Thanks:confused: :(
Hello,Quote:
Originally Posted by fw_mathis
For #1, plug in the x values given into "x"; so,
y = 1/(-2 - 2);
y = 1/(-2 - 1);... and so forth
You'll get the following answers,
y = -1/4, -1/3, -1/2, -1, undefined (since you get 1/0), 1 for x = -2, -1, 0, 1, 2, 3, respectively.
2.)
x - 2*sqrt(x) = 0
-2*sqrt(x) = -x
2*sqrt(x) = x
sqrt(x) = x/2
Square both sides;
x = x^2/4
x - x^2/4 = 0
(-x^2 + 4x)/4 = 0
-x^2 + 4x = 0
-x*(x - 4) = 0
x = 0 V x = 4
3.)Quote:
Originally Posted by fw_mathis
Let (0, 0) be your starting position.
You're at (75, 65);
You could either find the hypotenuse or use the distance formula (which is the same thing).
Using the distance formula:
d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)
d = sqrt((75 - 0)^2 + (65 - 0)^2)
d = sqrt(75^2 + 65^2)
d = sqrt(9850)
d = 5*sqrt(394)
d ~ 99.25 kilometers
Pythag:
a^2 + b^2 = c^2
a = 65
b = 75
Which is the distance formula. Do you see how?
65^2 + 75^2 = c^2 ...
4.) V = s^3
1000 = s^3
Solve for s;
s = 10 cm
